What is the answer to solvefor x,y=sqrt(x^2-Cx) ?

The answer to solvefor x,y=sqrt(x^2-Cx) is x=(C+sqrt(C^2+4y^2))/2 ,x=(C-sqrt(C^2+4y^2))/2

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solvefor x,y=sqrt(x^2-Cx)

solve for

x, y = x^{2} - C x

x = \frac{C + C ^{2} + 4 y ^{2}}{2}, x = \frac{C - C ^{2} + 4 y ^{2}}{2}

Solution steps

y = x^{2} - C x

Square both sides:

y^{2} = x^{2} - C x

y^{2} = x^{2} - C x

Solve

y^{2} = x^{2} - C x : x = \frac{C + C ^{2} + 4 y ^{2}}{2}, x = \frac{C - C ^{2} + 4 y ^{2}}{2}

x = \frac{C + C ^{2} + 4 y ^{2}}{2}, x = \frac{C - C ^{2} + 4 y ^{2}}{2}

x - 16 x^{\frac{1}{2}} - 512 = 0

a = 4 + 5 + a

1 + 2 = a - 1

x + 3 + 4 = 5

0.75 = 2 π \frac{8}{k}

What is the answer to solvefor x,y=sqrt(x^2-Cx) ?
The answer to solvefor x,y=sqrt(x^2-Cx) is x=(C+sqrt(C^2+4y^2))/2 ,x=(C-sqrt(C^2+4y^2))/2