What is the answer to solvefor x,sqrt(4p(x-h))+k=y ?

The answer to solvefor x,sqrt(4p(x-h))+k=y is x=(y^2-2ky+k^2+4ph)/(4p)

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solvefor x,sqrt(4p(x-h))+k=y

solve for

x, 4 p (x - h) + k = y

x = \frac{y ^{2} - 2 k y + k ^{2} + 4 p h}{4 p}

Solution steps

4 p (x - h) + k = y

Move

k

to the right side

4 p (x - h) = y - k

Square both sides:

4 p x - 4 p h = y^{2} - 2 k y + k^{2}

4 p x - 4 p h = y^{2} - 2 k y + k^{2}

Solve

4 p x - 4 p h = y^{2} - 2 k y + k^{2} : x = \frac{y ^{2} - 2 k y + k ^{2} + 4 p h}{4 p}

x = \frac{y ^{2} - 2 k y + k ^{2} + 4 p h}{4 p}

3 x + 3 - 6 = 0

x, x - 1 = y

16 + 6 + x = 12

4 = \frac{g}{0.5}

x = - x^{2}

What is the answer to solvefor x,sqrt(4p(x-h))+k=y ?
The answer to solvefor x,sqrt(4p(x-h))+k=y is x=(y^2-2ky+k^2+4ph)/(4p)