What is the answer to (1-y^2)^{1/2}=0 ?

The answer to (1-y^2)^{1/2}=0 is y=1,y=-1

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(1-y^2)^{1/2}=0

(1 - y^{2})^{\frac{1}{2}} = 0

y = 1, y = - 1

Solution steps

(1 - y^{2})^{\frac{1}{2}} = 0

Square both sides:

1 - y^{2} = 0

1 - y^{2} = 0

Solve

1 - y^{2} = 0 : y = 1, y = - 1

y = 1, y = - 1

Verify Solutions:

y = 1

True

, y = - 1

True

The solutions are

y = 1, y = - 1

x + 4 - 7 = 0

3 + 6 x - 11 = x

7 x - 6 - 7 = 3 x - 29

What is the answer to (1-y^2)^{1/2}=0 ?
The answer to (1-y^2)^{1/2}=0 is y=1,y=-1
Solve for y: (1-y^2)^{1/2}=0
The solution is y=1,y=-1