What is the answer to sqrt(2x+3)sqrt(x+2)=2 ?

The answer to sqrt(2x+3)sqrt(x+2)=2 is x=(-7+sqrt(33))/4

Solve for x: sqrt(2x+3)sqrt(x+2)=2

The solution is x=(-7+sqrt(33))/4

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2 x + 3 x + 2 = 2

x = \frac{- 7 + 33}{4}

Decimal Notation

x = - 0.31385 \dots

Solution steps

2 x + 3 x + 2 = 2

Square both sides:

2 x^{2} + 7 x + 6 = 4

2 x^{2} + 7 x + 6 = 4

Solve

2 x^{2} + 7 x + 6 = 4 : x = \frac{- 7 + 33}{4}, x = \frac{- 7 - 33}{4}

x = \frac{- 7 + 33}{4}, x = \frac{- 7 - 33}{4}

Verify Solutions:

x = \frac{- 7 + 33}{4}

True

, x = \frac{- 7 - 33}{4}

False

The solution is

x = \frac{- 7 + 33}{4}

x = 19

x + 9 = 11

- x x + 12 = x + 3

3 x - 1 - x + 2 = 1

x - 4 = 7 x - 34

What is the answer to sqrt(2x+3)sqrt(x+2)=2 ?
The answer to sqrt(2x+3)sqrt(x+2)=2 is x=(-7+sqrt(33))/4
Solve for x: sqrt(2x+3)sqrt(x+2)=2
The solution is x=(-7+sqrt(33))/4