What are the solutions to the equation 5x^2-4x=6 ?

The solutions to the equation 5x^2-4x=6 are x=(2+sqrt(34))/5 ,x=(2-sqrt(34))/5

Find the zeros of 5x^2-4x=6

The zeros of 5x^2-4x=6 are x=(2+sqrt(34))/5 ,x=(2-sqrt(34))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 4 x = 6

x = \frac{2 + 34}{5}, x = \frac{2 - 34}{5}

Decimal Notation

x = 1.56619 \dots, x = - 0.76619 \dots

Solution steps

5 x^{2} - 4 x = 6

Move

6

to the left side

5 x^{2} - 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 6) = 234

x_{1, 2} = \frac{- ( - 4 ) \pm 2 34}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 34}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 2 34}{2 \cdot 5}

x = \frac{- ( - 4 ) + 2 34}{2 \cdot 5} : \frac{2 + 34}{5}

x = \frac{- ( - 4 ) - 2 34}{2 \cdot 5} : \frac{2 - 34}{5}

The solutions to the quadratic equation are:

x = \frac{2 + 34}{5}, x = \frac{2 - 34}{5}

m^{2} - 9 m + 18

4 x^{2} + 7 = 29 x

i^{25}

(2 x + 3) (1 - 3 x) (x - 2) < 0

3 x^{2} - 15 x = 2 x + 6

What are the solutions to the equation 5x^2-4x=6 ?
The solutions to the equation 5x^2-4x=6 are x=(2+sqrt(34))/5 ,x=(2-sqrt(34))/5
Find the zeros of 5x^2-4x=6
The zeros of 5x^2-4x=6 are x=(2+sqrt(34))/5 ,x=(2-sqrt(34))/5