What is the answer to x^2+3x+6sqrt(x^2+3x)=16 ?

The answer to x^2+3x+6sqrt(x^2+3x)=16 is x=1,x=-4

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x^2+3x+6sqrt(x^2+3x)=16

x^{2} + 3 x + 6 x^{2} + 3 x = 16

x = 1, x = - 4

Solution steps

x^{2} + 3 x + 6 x^{2} + 3 x = 16

Remove square roots

36 x^{2} + 108 x = x^{4} + 6 x^{3} - 23 x^{2} - 96 x + 256

Solve

36 x^{2} + 108 x = x^{4} + 6 x^{3} - 23 x^{2} - 96 x + 256 : x = 1, x = - 4, x = \frac{- 3 + 265}{2}, x = \frac{- 3 - 265}{2}

x = 1, x = - 4, x = \frac{- 3 + 265}{2}, x = \frac{- 3 - 265}{2}

Verify Solutions:

x = 1

True

, x = - 4

True

, x = \frac{- 3 + 265}{2}

False

, x = \frac{- 3 - 265}{2}

False

The solutions are

x = 1, x = - 4

398.6 = 1377 x^{- 0.1153}

x^{\frac{- 3}{2}} = 8

k + 9 - k = 3

y^{\frac{4}{3}} = - 4 y

What is the answer to x^2+3x+6sqrt(x^2+3x)=16 ?
The answer to x^2+3x+6sqrt(x^2+3x)=16 is x=1,x=-4
Solve for x: x^2+3x+6sqrt(x^2+3x)=16
The solution is x=1,x=-4