What is the answer to solvefor x,a=sqrt(x^2-4) ?

The answer to solvefor x,a=sqrt(x^2-4) is x=sqrt(a^2+4) {a>= 0},x=-sqrt(a^2+4) {a>= 0}

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solvefor x,a=sqrt(x^2-4)

x, a = x^{2} - 4

x = a^{2} + 4 {a \geq 0}, x = - a^{2} + 4 {a \geq 0}

Solution steps

a = x^{2} - 4

Square both sides:

a^{2} = x^{2} - 4

a^{2} = x^{2} - 4

Solve

a^{2} = x^{2} - 4 : x = a^{2} + 4, x = - a^{2} + 4

x = a^{2} + 4, x = - a^{2} + 4

Verify Solutions:

x = a^{2} + 4 {a \geq 0}, x = - a^{2} + 4 {a \geq 0}

The solutions are

x = a^{2} + 4 {a \geq 0}, x = - a^{2} + 4 {a \geq 0}

\frac{1}{3} 2 x + 1 - 1 = 2

- 3 - 4 x + 1 = 0

x + 2 = - 2

70 e^{- 0.0144} \cdot 2 = 45

x^{\frac{7}{3}} = - 128

What is the answer to solvefor x,a=sqrt(x^2-4) ?
The answer to solvefor x,a=sqrt(x^2-4) is x=sqrt(a^2+4) {a>= 0},x=-sqrt(a^2+4) {a>= 0}