What is the answer to \sqrt[5]{x^2-4x}=2 ?

The answer to \sqrt[5]{x^2-4x}=2 is x=8,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\sqrt[5]{x^2-4x}=2

x = 8, x = - 4

Solution steps

Take both sides of the equation to the power of

5 : x^{2} - 4 x = 32

x^{2} - 4 x = 32

Solve

x^{2} - 4 x = 32 : x = 8, x = - 4

x = 8, x = - 4

Verify Solutions:

x = 8

True

, x = - 4

True

The solutions are

x = 8, x = - 4

x + 1 = 2 x

2 a - 2 a + 1 = - 1

x = - x + 2

- \frac{x}{25 - x ^{2}} = 4

3 x + 5 x^{2} + 11 - 5 = 0

What is the answer to \sqrt[5]{x^2-4x}=2 ?
The answer to \sqrt[5]{x^2-4x}=2 is x=8,x=-4
Solve for x: \sqrt[5]{x^2-4x}=2
The solution is x=8,x=-4