What is the answer to x^2=21+sqrt(x^2-9) ?

The answer to x^2=21+sqrt(x^2-9) is x=5,x=-5

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x^2=21+sqrt(x^2-9)

x^{2} = 21 + x^{2} - 9

x = 5, x = - 5

Solution steps

x^{2} = 21 + x^{2} - 9

Remove square roots

x^{4} - 42 x^{2} + 441 = x^{2} - 9

Solve

x^{4} - 42 x^{2} + 441 = x^{2} - 9 : x = 5, x = - 5, x = 32, x = - 32

x = 5, x = - 5, x = 32, x = - 32

Verify Solutions:

x = 5

True

, x = - 5

True

, x = 32

False

, x = - 32

False

The solutions are

x = 5, x = - 5

2 - 3 x - 5 = 0

y^{(\frac{1}{3})} = y - 10

u + 2 = 9

\frac{3 x - 2}{2 x - 1} = 1

What is the answer to x^2=21+sqrt(x^2-9) ?
The answer to x^2=21+sqrt(x^2-9) is x=5,x=-5
Solve for x: x^2=21+sqrt(x^2-9)
The solution is x=5,x=-5