What are the solutions to the equation 2(x+4)^2=64 ?

The solutions to the equation 2(x+4)^2=64 are x=4sqrt(2)-4,x=-4sqrt(2)-4

Find the zeros of 2(x+4)^2=64

The zeros of 2(x+4)^2=64 are x=4sqrt(2)-4,x=-4sqrt(2)-4

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2 (x + 4)^{2} = 64

x = 42 - 4, x = - 42 - 4

Decimal Notation

x = 1.65685 \dots, x = - 9.65685 \dots

Solution steps

2 (x + 4)^{2} = 64

Divide both sides by

2

(x + 4)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 32 : x = 42 - 4

Solve

x + 4 = - 32 : x = - 42 - 4

The solutions to the quadratic equation are:

x = 42 - 4, x = - 42 - 4

- \frac{1}{2} n + 6 = - 10

x + 6 \leq 2 (x + 1)

3 z^{2} - 4 z - 7

\frac{n}{2} + 7 = 22

5 x^{5} y - 405 x

What are the solutions to the equation 2(x+4)^2=64 ?
The solutions to the equation 2(x+4)^2=64 are x=4sqrt(2)-4,x=-4sqrt(2)-4
Find the zeros of 2(x+4)^2=64
The zeros of 2(x+4)^2=64 are x=4sqrt(2)-4,x=-4sqrt(2)-4