What is the answer to \sqrt[3]{x^2+x-4}=2 ?

The answer to \sqrt[3]{x^2+x-4}=2 is x=3,x=-4

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\sqrt[3]{x^2+x-4}=2

x = 3, x = - 4

Solution steps

Take both sides of the equation to the power of

3 : x^{2} + x - 4 = 8

x^{2} + x - 4 = 8

Solve

x^{2} + x - 4 = 8 : x = 3, x = - 4

x = 3, x = - 4

Verify Solutions:

x = 3

True

, x = - 4

True

The solutions are

x = 3, x = - 4

(5 x + 2)^{2} = 64

4 x - 3 = 4

x - 1 = 3 x + 1

u = 6

What is the answer to \sqrt[3]{x^2+x-4}=2 ?
The answer to \sqrt[3]{x^2+x-4}=2 is x=3,x=-4
Solve for x: \sqrt[3]{x^2+x-4}=2
The solution is x=3,x=-4