What is the answer to 2sqrt(10)=sqrt(k^2+4k+8) ?

The answer to 2sqrt(10)=sqrt(k^2+4k+8) is k=4,k=-8

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2sqrt(10)=sqrt(k^2+4k+8)

210 = k^{2} + 4 k + 8

k = 4, k = - 8

Solution steps

210 = k^{2} + 4 k + 8

Square both sides:

40 = k^{2} + 4 k + 8

40 = k^{2} + 4 k + 8

Solve

40 = k^{2} + 4 k + 8 : k = 4, k = - 8

k = 4, k = - 8

Verify Solutions:

k = 4

True

, k = - 8

True

The solutions are

k = 4, k = - 8

3 2 x + 1 = 4

25 - x^{2} = x + 1

4 x + 7 = x + 2

a - 1 - 7 - a = 1

x = x + 4

What is the answer to 2sqrt(10)=sqrt(k^2+4k+8) ?
The answer to 2sqrt(10)=sqrt(k^2+4k+8) is k=4,k=-8
Solve for k: 2sqrt(10)=sqrt(k^2+4k+8)
The solution is k=4,k=-8