What are the solutions to the equation 5x-4x^2=0 ?

The solutions to the equation 5x-4x^2=0 are x=0,x= 5/4

Find the zeros of 5x-4x^2=0

The zeros of 5x-4x^2=0 are x=0,x= 5/4

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5 x - 4 x^{2} = 0

x = 0, x = \frac{5}{4}

Decimal Notation

x = 0, x = 1.25

Solution steps

5 x - 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

5^{2} - 4 (- 4) \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 ( - 4 )}, x_{2} = \frac{- 5 - 5}{2 ( - 4 )}

x = \frac{- 5 + 5}{2 ( - 4 )} : 0

x = \frac{- 5 - 5}{2 ( - 4 )} : \frac{5}{4}

The solutions to the quadratic equation are:

x = 0, x = \frac{5}{4}

x^{2} y^{2} + x^{2} + y^{2} + 1

6 = n^{2} + 3 n - 12

- \frac{6}{9}

0 - y = 5

\frac{35 y ^{8} x ^{5}}{- 21 y ^{- 1} x ^{9}}

What are the solutions to the equation 5x-4x^2=0 ?
The solutions to the equation 5x-4x^2=0 are x=0,x= 5/4
Find the zeros of 5x-4x^2=0
The zeros of 5x-4x^2=0 are x=0,x= 5/4