What is the answer to solvefor y,x=sqrt(y-9) ?

The answer to solvefor y,x=sqrt(y-9) is y=x^2+9 {x>= 0}

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solvefor y,x=sqrt(y-9)

solve for

y, x = y - 9

y = x^{2} + 9 {x \geq 0}

Solution steps

x = y - 9

Square both sides:

x^{2} = y - 9

x^{2} = y - 9

Solve

x^{2} = y - 9 : y = x^{2} + 9

y = x^{2} + 9

Verify Solutions:

y = x^{2} + 9 {x \geq 0}

The solution is

y = x^{2} + 9 {x \geq 0}

4 = \frac{3 V}{3.14 ( 8 )}

x^{2} + 1 = 2 - x

y, x = y - 5

(x^{2} - x - 22)^{\frac{2}{3}} = 27

- 4 - 4 - m = - 4

What is the answer to solvefor y,x=sqrt(y-9) ?
The answer to solvefor y,x=sqrt(y-9) is y=x^2+9 {x>= 0}