What is the answer to solvefor x,y=\sqrt[3]{3x} ?

The answer to solvefor x,y=\sqrt[3]{3x} is x=(y^3)/3

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solvefor x,y=\sqrt[3]{3x}

solve for

x = \frac{y ^{3}}{3}

Solution steps

Take both sides of the equation to the power of

3 : y^{3} = 3 x

y^{3} = 3 x

Solve

y^{3} = 3 x : x = \frac{y ^{3}}{3}

x = \frac{y ^{3}}{3}

Verify Solutions:

x = \frac{y ^{3}}{3}

True

The solution is

x = \frac{y ^{3}}{3}

10 x - x + x = - 2

5 x^{\frac{3}{2}} - 35 = 0

\frac{x + 2}{x - 1} = 0

- 9 = - a + 41 - 4 a

330 = λ^{0.2}

What is the answer to solvefor x,y=\sqrt[3]{3x} ?
The answer to solvefor x,y=\sqrt[3]{3x} is x=(y^3)/3