What is the answer to 2=(k+sqrt(k^2+8))/2 ?

The answer to 2=(k+sqrt(k^2+8))/2 is k=1

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2=(k+sqrt(k^2+8))/2

2 = \frac{k + k ^{2} + 8}{2}

k = 1

Solution steps

2 = \frac{k + k ^{2} + 8}{2}

Multiply both sides by

2

2 \cdot 2 = \frac{k + k ^{2} + 8}{2} \cdot 2

Simplify

4 = k + k^{2} + 8

Remove square roots

16 - 8 k + k^{2} = k^{2} + 8

Solve

16 - 8 k + k^{2} = k^{2} + 8 : k = 1

k = 1

Verify Solutions:

k = 1

True

The solution is

k = 1

x + 8 = 3 x + 16

(2 x + 2)^{\frac{1}{3}} + 6 = 8

6 + 3 x - 4 = 24

- 6 x + 4 = - 56

2 - y = y + 4

What is the answer to 2=(k+sqrt(k^2+8))/2 ?
The answer to 2=(k+sqrt(k^2+8))/2 is k=1
Solve for k: 2=(k+sqrt(k^2+8))/2
The solution is k=1