What is the answer to \sqrt[3]{2x-3}=2 ?

The answer to \sqrt[3]{2x-3}=2 is x= 11/2

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\sqrt[3]{2x-3}=2

x = \frac{11}{2}

Decimal Notation

x = 5.5

Solution steps

Take both sides of the equation to the power of

3 : 2 x - 3 = 8

2 x - 3 = 8

Solve

2 x - 3 = 8 : x = \frac{11}{2}

x = \frac{11}{2}

Verify Solutions:

x = \frac{11}{2}

True

The solution is

x = \frac{11}{2}

5 x + 7 = 5 + 7

225 - 15 x^{2} = 0

v = 11 v - 28

2 x + 2 - 3 (x + 1)^{\frac{2}{3}} = 0

y, x = 10 y^{\frac{1}{3}}

What is the answer to \sqrt[3]{2x-3}=2 ?
The answer to \sqrt[3]{2x-3}=2 is x= 11/2
Solve for x: \sqrt[3]{2x-3}=2
The solution is x= 11/2