What is the answer to sqrt(3x-1)+sqrt(3x+2)=2 ?

The answer to sqrt(3x-1)+sqrt(3x+2)=2 is x= 17/48

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sqrt(3x-1)+sqrt(3x+2)=2

3 x - 1 + 3 x + 2 = 2

x = \frac{17}{48}

Decimal Notation

x = 0.35416 \dots

Solution steps

3 x - 1 + 3 x + 2 = 2

Remove square roots

49 = 48 x + 32

Solve

49 = 48 x + 32 : x = \frac{17}{48}

x = \frac{17}{48}

Verify Solutions:

x = \frac{17}{48}

True

The solution is

x = \frac{17}{48}

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What is the answer to sqrt(3x-1)+sqrt(3x+2)=2 ?
The answer to sqrt(3x-1)+sqrt(3x+2)=2 is x= 17/48
Solve for x: sqrt(3x-1)+sqrt(3x+2)=2
The solution is x= 17/48