What is the answer to 4(\sqrt[3]{x-2})+1=9 ?

The answer to 4(\sqrt[3]{x-2})+1=9 is x=10

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4(\sqrt[3]{x-2})+1=9

x = 10

Solution steps

Move

1

to the right side

Divide both sides by

4

Take both sides of the equation to the power of

3 : x - 2 = 8

x - 2 = 8

Solve

x - 2 = 8 : x = 10

x = 10

Verify Solutions:

x = 10

True

The solution is

x = 10

x - 2 = x - 3

\frac{2}{5} 10 x + 6 = 12

6 + 3 x + 1 - 2 x = 0

x^{2} = 19

10100 = 10 100 - p

What is the answer to 4(\sqrt[3]{x-2})+1=9 ?
The answer to 4(\sqrt[3]{x-2})+1=9 is x=10
Solve for x: 4(\sqrt[3]{x-2})+1=9
The solution is x=10