What is the answer to sqrt(2x^2-7x-3)+x=3 ?

The answer to sqrt(2x^2-7x-3)+x=3 is x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sqrt(2x^2-7x-3)+x=3

2 x^{2} - 7 x - 3 + x = 3

x = - 3

Solution steps

2 x^{2} - 7 x - 3 + x = 3

Remove square roots

2 x^{2} - 7 x - 3 = 9 - 6 x + x^{2}

Solve

2 x^{2} - 7 x - 3 = 9 - 6 x + x^{2} : x = 4, x = - 3

x = 4, x = - 3

Verify Solutions:

x = 4

False

, x = - 3

True

The solution is

x = - 3

0 = 4 (x^{2} - 1)^{\frac{2}{3}}

2 x 4 - x - 3 4 - x = 0

7 = m + 3

2 = (1 + x)^{1.5}

(x - 2)^{\frac{1}{2}} + 4 = x

What is the answer to sqrt(2x^2-7x-3)+x=3 ?
The answer to sqrt(2x^2-7x-3)+x=3 is x=-3
Solve for x: sqrt(2x^2-7x-3)+x=3
The solution is x=-3