What are the solutions to the equation 4x^2-25=0 ?

The solutions to the equation 4x^2-25=0 are x= 5/2 ,x=-5/2

Find the zeros of 4x^2-25=0

The zeros of 4x^2-25=0 are x= 5/2 ,x=-5/2

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4 x^{2} - 25 = 0

x = \frac{5}{2}, x = - \frac{5}{2}

Solution steps

4 x^{2} - 25 = 0

Move

25

to the right side

4 x^{2} = 25

Divide both sides by

4

x^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{4}, x = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

x^{2} + 2 x + 1 = 49

x^{2} - 7 x - 12 = 0

2 - \frac{3}{4}

\frac{d}{4} = 10

3 c + 9 5 d

What are the solutions to the equation 4x^2-25=0 ?
The solutions to the equation 4x^2-25=0 are x= 5/2 ,x=-5/2
Find the zeros of 4x^2-25=0
The zeros of 4x^2-25=0 are x= 5/2 ,x=-5/2