What is the answer to (u+sqrt(u^2-64))/8 =1 ?

The answer to (u+sqrt(u^2-64))/8 =1 is u=8

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(u+sqrt(u^2-64))/8 =1

\frac{u + u ^{2} - 64}{8} = 1

u = 8

Solution steps

\frac{u + u ^{2} - 64}{8} = 1

Multiply both sides by

8

\frac{u + u ^{2} - 64}{8} \cdot 8 = 1 \cdot 8

Simplify

u + u^{2} - 64 = 8

Remove square roots

u^{2} - 64 = 64 - 16 u + u^{2}

Solve

u^{2} - 64 = 64 - 16 u + u^{2} : u = 8

u = 8

Verify Solutions:

u = 8

True

The solution is

u = 8

x - c^{2} + a = 2 b

G (x) = - 25 - x^{2}

5 x + 3 + 5 x + 2 = 21

3 t + 4 = 3

What is the answer to (u+sqrt(u^2-64))/8 =1 ?
The answer to (u+sqrt(u^2-64))/8 =1 is u=8
Solve for u: (u+sqrt(u^2-64))/8 =1
The solution is u=8