What is the answer to x^2+sqrt(x+1)=1 ?

The answer to x^2+sqrt(x+1)=1 is x=0,x=-1,x=(1-sqrt(5))/2

Solve for x: x^2+sqrt(x+1)=1

The solution is x=0,x=-1,x=(1-sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + x + 1 = 1

x = 0, x = - 1, x = \frac{1 - 5}{2}

Decimal Notation

x = 0, x = - 1, x = - 0.61803 \dots

Solution steps

x^{2} + x + 1 = 1

Remove square roots

x + 1 = 1 - 2 x^{2} + x^{4}

Solve

x + 1 = 1 - 2 x^{2} + x^{4} : x = 0, x = - 1, x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

x = 0, x = - 1, x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

Verify Solutions:

x = 0

True

, x = - 1

True

, x = \frac{1 + 5}{2}

False

, x = \frac{1 - 5}{2}

True

The solutions are

x = 0, x = - 1, x = \frac{1 - 5}{2}

2 x - 3 x - 5 = 9

x - x + 2 = 0

(7 x + 1)^{\frac{1}{2}} = 6

x - x = 72

0 = x x + 6

What is the answer to x^2+sqrt(x+1)=1 ?
The answer to x^2+sqrt(x+1)=1 is x=0,x=-1,x=(1-sqrt(5))/2
Solve for x: x^2+sqrt(x+1)=1
The solution is x=0,x=-1,x=(1-sqrt(5))/2