What is the answer to \sqrt[4]{9x^2-8}=x ?

The answer to \sqrt[4]{9x^2-8}=x is x=2sqrt(2),x=1

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\sqrt[4]{9x^2-8}=x

x = 22, x = 1

Decimal Notation

x = 2.82842 \dots, x = 1

Solution steps

Take both sides of the equation to the power of

4 : 9 x^{2} - 8 = x^{4}

9 x^{2} - 8 = x^{4}

Solve

9 x^{2} - 8 = x^{4} : x = 22, x = - 22, x = 1, x = - 1

x = 22, x = - 22, x = 1, x = - 1

Verify Solutions:

x = 22

True

, x = - 22

False

, x = 1

True

, x = - 1

False

The solutions are

x = 22, x = 1

7 = x + 1 + 4

14 - 5 x = x - 4

7 - 3 x + 3 = 8

5 x - 2 - 3 = 0

x - 2 = 2 x - 1

What is the answer to \sqrt[4]{9x^2-8}=x ?
The answer to \sqrt[4]{9x^2-8}=x is x=2sqrt(2),x=1
Solve for x: \sqrt[4]{9x^2-8}=x
The solution is x=2sqrt(2),x=1