What is the answer to (x^2+3x-10)^{2/3}=4 ?

The answer to (x^2+3x-10)^{2/3}=4 is x=3,x=-6,x=(-3+17^{1/2})/2 ,x=(-3-17^{1/2})/2

Solve for x: (x^2+3x-10)^{2/3}=4

The solution is x=3,x=-6,x=(-3+17^{1/2})/2 ,x=(-3-17^{1/2})/2

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(x^{2} + 3 x - 10)^{\frac{2}{3}} = 4

x = 3, x = - 6, x = \frac{- 3 + 1 7 ^{\frac{1}{2}}}{2}, x = \frac{- 3 - 1 7 ^{\frac{1}{2}}}{2}

Decimal Notation

x = 3, x = - 6, x = 0.56155 \dots, x = - 3.56155 \dots

Solution steps

(x^{2} + 3 x - 10)^{\frac{2}{3}} = 4

Take both sides of the equation to the power of

3 : (x^{2} + 3 x - 10)^{2} = 64

(x^{2} + 3 x - 10)^{2} = 64

Solve

(x^{2} + 3 x - 10)^{2} = 64 : x = 3, x = - 6, x = \frac{- 3 + 1 7 ^{\frac{1}{2}}}{2}, x = \frac{- 3 - 1 7 ^{\frac{1}{2}}}{2}

x = 3, x = - 6, x = \frac{- 3 + 1 7 ^{\frac{1}{2}}}{2}, x = \frac{- 3 - 1 7 ^{\frac{1}{2}}}{2}

Verify Solutions:

x = 3

True

, x = - 6

True

, x = \frac{- 3 + 1 7 ^{\frac{1}{2}}}{2}

True

, x = \frac{- 3 - 1 7 ^{\frac{1}{2}}}{2}

True

The solutions are

x = 3, x = - 6, x = \frac{- 3 + 1 7 ^{\frac{1}{2}}}{2}, x = \frac{- 3 - 1 7 ^{\frac{1}{2}}}{2}

x = - 1 + 4 x

x + 32 - x - 16 = 4

2 x + 40 + 4 = x

z, 4 z + 9 = cz + 8

x^{2} - 5 x + 4 = 0

What is the answer to (x^2+3x-10)^{2/3}=4 ?
The answer to (x^2+3x-10)^{2/3}=4 is x=3,x=-6,x=(-3+17^{1/2})/2 ,x=(-3-17^{1/2})/2
Solve for x: (x^2+3x-10)^{2/3}=4
The solution is x=3,x=-6,x=(-3+17^{1/2})/2 ,x=(-3-17^{1/2})/2