What is the answer to sqrt(x^2+2-x)=2 ?

The answer to sqrt(x^2+2-x)=2 is x=2,x=-1

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sqrt(x^2+2-x)=2

x^{2} + 2 - x = 2

x = 2, x = - 1

Solution steps

x^{2} + 2 - x = 2

Square both sides:

x^{2} + 2 - x = 4

x^{2} + 2 - x = 4

Solve

x^{2} + 2 - x = 4 : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2

True

, x = - 1

True

The solutions are

x = 2, x = - 1

6 x^{2} - x - 6 = 0

1.5 = 2.18 (1.55 - x)^{\frac{3}{2}}

2.5 = 2 π \frac{l}{3.711}

3 m^{\frac{1}{5}} + 9 = 0

x + 2 x - 3 - 9 = 0

What is the answer to sqrt(x^2+2-x)=2 ?
The answer to sqrt(x^2+2-x)=2 is x=2,x=-1
Solve for x: sqrt(x^2+2-x)=2
The solution is x=2,x=-1