What is the answer to 2x-1/(x^{1/2)}=0 ?

The answer to 2x-1/(x^{1/2)}=0 is x= 1/(\sqrt[3]{4)}

Solve for x: 2x-1/(x^{1/2)}=0

The solution is x= 1/(\sqrt[3]{4)}

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2 x - \frac{1}{x ^{\frac{1}{2}}} = 0

Decimal Notation

x = 0.62996 \dots

Solution steps

2 x - \frac{1}{x ^{\frac{1}{2}}} = 0

Multiply both sides by

x^{\frac{1}{2}}

2 x x^{\frac{1}{2}} - \frac{1}{x ^{\frac{1}{2}}} x^{\frac{1}{2}} = 0 \cdot x^{\frac{1}{2}}

Simplify

2 x^{\frac{1}{2}} x - 1 = 0

Remove square roots

4 x^{3} = 1

Solve

Verify Solutions:

True

The solution is

3 q + 2 = 5

\frac{1}{4} x - 3 - 5 = - 3

1.5 = 2.18 (x - 1.72)^{\frac{3}{2}}

- x^{2} + 4 x = 0

a^{2} + (2.75 a)^{2} = 150

What is the answer to 2x-1/(x^{1/2)}=0 ?
The answer to 2x-1/(x^{1/2)}=0 is x= 1/(\sqrt[3]{4)}
Solve for x: 2x-1/(x^{1/2)}=0
The solution is x= 1/(\sqrt[3]{4)}