What is the answer to sqrt((2+1)^2+(k-1)^2)=5 ?

The answer to sqrt((2+1)^2+(k-1)^2)=5 is k=5,k=-3

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sqrt((2+1)^2+(k-1)^2)=5

(2 + 1)^{2} + (k - 1)^{2} = 5

k = 5, k = - 3

Solution steps

(2 + 1)^{2} + (k - 1)^{2} = 5

Square both sides:

k^{2} - 2 k + 10 = 25

k^{2} - 2 k + 10 = 25

Solve

k^{2} - 2 k + 10 = 25 : k = 5, k = - 3

k = 5, k = - 3

Verify Solutions:

k = 5

True

, k = - 3

True

The solutions are

k = 5, k = - 3

x + 3 + x = x

x^{- \frac{1}{4}} = 2

4 x + 3 = 15

(x - 3)^{2} = 8

(90 - x)^{\frac{1}{2}} = x

What is the answer to sqrt((2+1)^2+(k-1)^2)=5 ?
The answer to sqrt((2+1)^2+(k-1)^2)=5 is k=5,k=-3
Solve for k: sqrt((2+1)^2+(k-1)^2)=5
The solution is k=5,k=-3