What is the answer to x+16=sqrt(3x^2) ?

The answer to x+16=sqrt(3x^2) is x=-8(sqrt(3)-1),x=8(1+sqrt(3))

Solve for x: x+16=sqrt(3x^2)

The solution is x=-8(sqrt(3)-1),x=8(1+sqrt(3))

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x + 16 = 3 x^{2}

x = - 8 (3 - 1), x = 8 (1 + 3)

Decimal Notation

x = - 5.85640 \dots, x = 21.85640 \dots

Solution steps

x + 16 = 3 x^{2}

Square both sides:

x^{2} + 32 x + 256 = 3 x^{2}

x^{2} + 32 x + 256 = 3 x^{2}

Solve

x^{2} + 32 x + 256 = 3 x^{2} : x = - 8 (3 - 1), x = 8 (1 + 3)

x = - 8 (3 - 1), x = 8 (1 + 3)

Verify Solutions:

x = - 8 (3 - 1)

True

, x = 8 (1 + 3)

True

The solutions are

x = - 8 (3 - 1), x = 8 (1 + 3)

2 x + 6 = 4 x^{2}

5 - x + 1 = x - 2

8 x - 7 = 3

5 x + 6 = 1

35 = 35.09 1^{2} + v^{2}

What is the answer to x+16=sqrt(3x^2) ?
The answer to x+16=sqrt(3x^2) is x=-8(sqrt(3)-1),x=8(1+sqrt(3))
Solve for x: x+16=sqrt(3x^2)
The solution is x=-8(sqrt(3)-1),x=8(1+sqrt(3))