What is the answer to |x-x^2|=0 ?

The answer to |x-x^2|=0 is x=0\lor x=1

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|x-x^2|=0

x - x^{2} = 0

x = 0 or x = 1

Solution steps

x - x^{2} = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

x - x^{2} = 0

x - x^{2} = 0 : x = 0, x = 1

x = 0 or x = 1

\frac{7 !}{( 7 - 2 ) ! 2 !}

4 x^{2} + 24 x = 0

\frac{( 2 x + 1 )}{x - 4} \leq 3

∣ x - 9 ∣ \leq 3

(- \frac{1}{2})^{2} + (\frac{3}{2})^{2}