What are the solutions to the equation 4x^2+24x=0 ?

The solutions to the equation 4x^2+24x=0 are x=0,x=-6

Find the zeros of 4x^2+24x=0

The zeros of 4x^2+24x=0 are x=0,x=-6

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4 x^{2} + 24 x = 0

x = 0, x = - 6

Solution steps

4 x^{2} + 24 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 \cdot 0 = 24

x_{1, 2} = \frac{- 24 \pm 24}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 24 + 24}{2 \cdot 4}, x_{2} = \frac{- 24 - 24}{2 \cdot 4}

x = \frac{- 24 + 24}{2 \cdot 4} : 0

x = \frac{- 24 - 24}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

\frac{( 2 x + 1 )}{x - 4} \leq 3

∣ x - 9 ∣ \leq 3

(- \frac{1}{2})^{2} + (\frac{3}{2})^{2}

8 p + 7 = - 121

\frac{25}{7 m ^{2} + 9} + \frac{14 m - 11}{7 m ^{2} + 9}

What are the solutions to the equation 4x^2+24x=0 ?
The solutions to the equation 4x^2+24x=0 are x=0,x=-6
Find the zeros of 4x^2+24x=0
The zeros of 4x^2+24x=0 are x=0,x=-6