What is the answer to solvefor x,sqrt(x)-y=3 ?

The answer to solvefor x,sqrt(x)-y=3 is x=9+6y+y^2 {y>=-3}

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solvefor x,sqrt(x)-y=3

solve for

x, x - y = 3

x = 9 + 6 y + y^{2} {y \geq - 3}

Solution steps

x - y = 3

Move

y

to the right side

x = 3 + y

Square both sides:

x = 9 + 6 y + y^{2}

x = 9 + 6 y + y^{2}

Verify Solutions:

x = 9 + 6 y + y^{2} {y \geq - 3}

The solution is

x = 9 + 6 y + y^{2} {y \geq - 3}

2 x + 2 = 0

2 x + 2 = 2

x - 5 + 9 = 11

2 x + 1 = 1 - x

(x - 3)^{\frac{2}{5}} = 9

What is the answer to solvefor x,sqrt(x)-y=3 ?
The answer to solvefor x,sqrt(x)-y=3 is x=9+6y+y^2 {y>=-3}