What is the answer to solvefor x,sqrt(x)+y=2 ?

The answer to solvefor x,sqrt(x)+y=2 is x=4-4y+y^2 {y<= 2}

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solvefor x,sqrt(x)+y=2

solve for

x, x + y = 2

x = 4 - 4 y + y^{2} {y \leq 2}

Solution steps

x + y = 2

Move

y

to the right side

x = 2 - y

Square both sides:

x = 4 - 4 y + y^{2}

x = 4 - 4 y + y^{2}

Verify Solutions:

x = 4 - 4 y + y^{2} {y \leq 2}

The solution is

x = 4 - 4 y + y^{2} {y \leq 2}

x - 5 - 2 x = 0

w = 7

10 - 3 x = 650 + 5 x

4 - x = 4 - x^{2}

2 x = 4 x^{2} + 6 x - 12

What is the answer to solvefor x,sqrt(x)+y=2 ?
The answer to solvefor x,sqrt(x)+y=2 is x=4-4y+y^2 {y<= 2}