What is the answer to sqrt((x-3)^2+(-1-2)^2)=4 ?

The answer to sqrt((x-3)^2+(-1-2)^2)=4 is x=3+sqrt(7),x=3-sqrt(7)

Solve for x: sqrt((x-3)^2+(-1-2)^2)=4

The solution is x=3+sqrt(7),x=3-sqrt(7)

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(x - 3)^{2} + (- 1 - 2)^{2} = 4

x = 3 + 7, x = 3 - 7

Decimal Notation

x = 5.64575 \dots, x = 0.35424 \dots

Solution steps

(x - 3)^{2} + (- 1 - 2)^{2} = 4

Square both sides:

x^{2} - 6 x + 18 = 16

x^{2} - 6 x + 18 = 16

Solve

x^{2} - 6 x + 18 = 16 : x = 3 + 7, x = 3 - 7

x = 3 + 7, x = 3 - 7

Verify Solutions:

x = 3 + 7

True

, x = 3 - 7

True

The solutions are

x = 3 + 7, x = 3 - 7

7 x + 4 = 5

\frac{x - 1}{x + 1} = 1

x^{2} - 17 - 8 = 0

x, y = 2 x - 1

6 x - 2 x = 4

What is the answer to sqrt((x-3)^2+(-1-2)^2)=4 ?
The answer to sqrt((x-3)^2+(-1-2)^2)=4 is x=3+sqrt(7),x=3-sqrt(7)
Solve for x: sqrt((x-3)^2+(-1-2)^2)=4
The solution is x=3+sqrt(7),x=3-sqrt(7)