What is the answer to sqrt(x^2+1)=4 ?

The answer to sqrt(x^2+1)=4 is x=sqrt(15),x=-sqrt(15)

Solve for x: sqrt(x^2+1)=4

The solution is x=sqrt(15),x=-sqrt(15)

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Popular >

x^{2} + 1 = 4

x = 15, x = - 15

Decimal Notation

x = 3.87298 \dots, x = - 3.87298 \dots

Solution steps

x^{2} + 1 = 4

Square both sides:

x^{2} + 1 = 16

x^{2} + 1 = 16

Solve

x^{2} + 1 = 16 : x = 15, x = - 15

x = 15, x = - 15

Verify Solutions:

x = 15

True

, x = - 15

True

The solutions are

x = 15, x = - 15

x^{2} + 1 = 5

x^{2} + 1 = 2

x + 3 + 4 - x = 3

10 v - 6 v + 8 = 3 v

b - 1 = 7 b - 7

What is the answer to sqrt(x^2+1)=4 ?
The answer to sqrt(x^2+1)=4 is x=sqrt(15),x=-sqrt(15)
Solve for x: sqrt(x^2+1)=4
The solution is x=sqrt(15),x=-sqrt(15)