What is the answer to solvefor x,\sqrt[3]{x}-y=1 ?

The answer to solvefor x,\sqrt[3]{x}-y=1 is x=1+3y+3y^2+y^3

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solvefor x,\sqrt[3]{x}-y=1

solve for

x = 1 + 3 y + 3 y^{2} + y^{3}

Solution steps

Move

y

to the right side

Take both sides of the equation to the power of

3 : x = 1 + 3 y + 3 y^{2} + y^{3}

x = 1 + 3 y + 3 y^{2} + y^{3}

Verify Solutions:

x = 1 + 3 y + 3 y^{2} + y^{3}

True

The solution is

x = 1 + 3 y + 3 y^{2} + y^{3}

1 + x^{2} = 5 - x^{2}

x = 12 - x

x^{\frac{1}{2}} = 2 x - 15

x - 4 + 4 = 6

600 = k + k

What is the answer to solvefor x,\sqrt[3]{x}-y=1 ?
The answer to solvefor x,\sqrt[3]{x}-y=1 is x=1+3y+3y^2+y^3