What is the answer to sqrt(3m^2+(m+3)^2)=9 ?

The answer to sqrt(3m^2+(m+3)^2)=9 is m=(3(sqrt(33)-1))/4 ,m=-(3(1+sqrt(33)))/4

Solve for m: sqrt(3m^2+(m+3)^2)=9

The solution is m=(3(sqrt(33)-1))/4 ,m=-(3(1+sqrt(33)))/4

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3 m^{2} + (m + 3)^{2} = 9

m = \frac{3 ( 33 - 1 )}{4}, m = - \frac{3 ( 1 + 33 )}{4}

Decimal Notation

m = 3.55842 \dots, m = - 5.05842 \dots

Solution steps

3 m^{2} + (m + 3)^{2} = 9

Square both sides:

4 m^{2} + 6 m + 9 = 81

4 m^{2} + 6 m + 9 = 81

Solve

4 m^{2} + 6 m + 9 = 81 : m = \frac{3 ( 33 - 1 )}{4}, m = - \frac{3 ( 1 + 33 )}{4}

m = \frac{3 ( 33 - 1 )}{4}, m = - \frac{3 ( 1 + 33 )}{4}

Verify Solutions:

m = \frac{3 ( 33 - 1 )}{4}

True

, m = - \frac{3 ( 1 + 33 )}{4}

True

The solutions are

m = \frac{3 ( 33 - 1 )}{4}, m = - \frac{3 ( 1 + 33 )}{4}

5 x^{2} - 6 x = 5 x - 6

y^{\frac{2}{3}} = 2 - y^{4}

x^{2} = x^{2}

6 x + 100 + 10 = x

(- 6 n)^{2} + (- 8 n)^{2} = 3

What is the answer to sqrt(3m^2+(m+3)^2)=9 ?
The answer to sqrt(3m^2+(m+3)^2)=9 is m=(3(sqrt(33)-1))/4 ,m=-(3(1+sqrt(33)))/4
Solve for m: sqrt(3m^2+(m+3)^2)=9
The solution is m=(3(sqrt(33)-1))/4 ,m=-(3(1+sqrt(33)))/4