What is the answer to 3y+2=sqrt(y^2+10y+7) ?

The answer to 3y+2=sqrt(y^2+10y+7) is y= 1/2

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3y+2=sqrt(y^2+10y+7)

3 y + 2 = y^{2} + 10 y + 7

y = \frac{1}{2}

Decimal Notation

y = 0.5

Solution steps

3 y + 2 = y^{2} + 10 y + 7

Square both sides:

9 y^{2} + 12 y + 4 = y^{2} + 10 y + 7

9 y^{2} + 12 y + 4 = y^{2} + 10 y + 7

Solve

9 y^{2} + 12 y + 4 = y^{2} + 10 y + 7 : y = \frac{1}{2}, y = - \frac{3}{4}

y = \frac{1}{2}, y = - \frac{3}{4}

Verify Solutions:

y = \frac{1}{2}

True

, y = - \frac{3}{4}

False

The solution is

y = \frac{1}{2}

7 x^{\frac{9}{4}} + 13 = 70543885

2 - x^{2} = x^{2}

2 x + 1 + 5 = 0

6 = \frac{1}{2 81 a + 162}

What is the answer to 3y+2=sqrt(y^2+10y+7) ?
The answer to 3y+2=sqrt(y^2+10y+7) is y= 1/2
Solve for y: 3y+2=sqrt(y^2+10y+7)
The solution is y= 1/2