What is the answer to sqrt(2x^2)=sqrt(-3+7x) ?

The answer to sqrt(2x^2)=sqrt(-3+7x) is x=3,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sqrt(2x^2)=sqrt(-3+7x)

2 x^{2} = - 3 + 7 x

x = 3, x = \frac{1}{2}

Decimal Notation

x = 3, x = 0.5

Solution steps

2 x^{2} = - 3 + 7 x

Square both sides:

2 x^{2} = - 3 + 7 x

2 x^{2} = - 3 + 7 x

Solve

2 x^{2} = - 3 + 7 x : x = 3, x = \frac{1}{2}

x = 3, x = \frac{1}{2}

Verify Solutions:

x = 3

True

, x = \frac{1}{2}

True

The solutions are

x = 3, x = \frac{1}{2}

- 7 \cdot x = - 25 - x^{2}

2 - \frac{2}{x ^{\frac{1}{3}}} = 0

0 = 2 \cdot 3 π t^{\frac{1}{5}}

5 x - 3 - 3 = 0

\frac{1}{2 4 - t} = 0

What is the answer to sqrt(2x^2)=sqrt(-3+7x) ?
The answer to sqrt(2x^2)=sqrt(-3+7x) is x=3,x= 1/2
Solve for x: sqrt(2x^2)=sqrt(-3+7x)
The solution is x=3,x= 1/2