What is the answer to 3=sqrt(4+(1+y)^2) ?

The answer to 3=sqrt(4+(1+y)^2) is y=-1+sqrt(5),y=-1-sqrt(5)

Solve for y: 3=sqrt(4+(1+y)^2)

The solution is y=-1+sqrt(5),y=-1-sqrt(5)

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3 = 4 + (1 + y)^{2}

y = - 1 + 5, y = - 1 - 5

Decimal Notation

y = 1.23606 \dots, y = - 3.23606 \dots

Solution steps

3 = 4 + (1 + y)^{2}

Square both sides:

9 = y^{2} + 2 y + 5

9 = y^{2} + 2 y + 5

Solve

9 = y^{2} + 2 y + 5 : y = - 1 + 5, y = - 1 - 5

y = - 1 + 5, y = - 1 - 5

Verify Solutions:

y = - 1 + 5

True

, y = - 1 - 5

True

The solutions are

y = - 1 + 5, y = - 1 - 5

4 2 x + 3 = 6 x + 1

y, x = y^{2} + 2 y

(1 - x)^{0.5} = \frac{3}{2}

(x) = x^{\frac{1}{3}} (x + 4)

p^{\frac{- 5}{2}} = 2^{- 5}

What is the answer to 3=sqrt(4+(1+y)^2) ?
The answer to 3=sqrt(4+(1+y)^2) is y=-1+sqrt(5),y=-1-sqrt(5)
Solve for y: 3=sqrt(4+(1+y)^2)
The solution is y=-1+sqrt(5),y=-1-sqrt(5)