What is the answer to 0=x^4-\sqrt[3]{x} ?

The answer to 0=x^4-\sqrt[3]{x} is x=0,x=1

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0=x^4-\sqrt[3]{x}

x = 0, x = 1

Solution steps

Remove roots

- x^{12} = - x

Solve

- x^{12} = - x : x = 0, x = 1

x = 0, x = 1

Verify Solutions:

x = 0

True

, x = 1

True

The solutions are

x = 0, x = 1

(5 x + 2)^{\frac{4}{3}} = 256

9 y + 4 - y + 4 = 4

4 x + 9 - 1 = x

5 = 2 π \frac{l}{10}

x, x - 2 + 4 = x

What is the answer to 0=x^4-\sqrt[3]{x} ?
The answer to 0=x^4-\sqrt[3]{x} is x=0,x=1
Solve for x: 0=x^4-\sqrt[3]{x}
The solution is x=0,x=1