What is the answer to solvefor d,q=sqrt(Fd+4) ?

The answer to solvefor d,q=sqrt(Fd+4) is d=(q^2-4)/F

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solvefor d,q=sqrt(Fd+4)

solve for

d, q = F d + 4

d = \frac{q ^{2} - 4}{F}

Solution steps

q = F d + 4

Square both sides:

q^{2} = F d + 4

q^{2} = F d + 4

Solve

q^{2} = F d + 4 : d = \frac{q ^{2} - 4}{F}

d = \frac{q ^{2} - 4}{F}

x + 2 x - 3 = 0

x^{\frac{4}{3}} = 9

y, x = 2 3 - y

x^{2} - 2 5 x + 5 = 0

1 - x = 19

What is the answer to solvefor d,q=sqrt(Fd+4) ?
The answer to solvefor d,q=sqrt(Fd+4) is d=(q^2-4)/F