What is the answer to x^{(-2)/3}=4 ?

The answer to x^{(-2)/3}=4 is x= 1/8 ,x=-1/8

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x^{(-2)/3}=4

x^{\frac{- 2}{3}} = 4

x = \frac{1}{8}, x = - \frac{1}{8}

Decimal Notation

x = 0.125, x = - 0.125

Solution steps

x^{\frac{- 2}{3}} = 4

Take both sides of the equation to the power of

- 3 : x^{2} = \frac{1}{64}

x^{2} = \frac{1}{64}

Solve

x^{2} = \frac{1}{64} : x = \frac{1}{8}, x = - \frac{1}{8}

x = \frac{1}{8}, x = - \frac{1}{8}

Verify Solutions:

x = \frac{1}{8}

True

, x = - \frac{1}{8}

True

The solutions are

x = \frac{1}{8}, x = - \frac{1}{8}

3 x + 27 = x + 3

3 b = b^{0.3}

u + 5 - 1 = u - 2

(x + 3)^{\frac{2}{3}} = 4

x x^{2} + 3 = - x + 3

What is the answer to x^{(-2)/3}=4 ?
The answer to x^{(-2)/3}=4 is x= 1/8 ,x=-1/8
Solve for x: x^{(-2)/3}=4
The solution is x= 1/8 ,x=-1/8