What is the answer to solvefor m,sqrt(m-7)=n+3 ?

The answer to solvefor m,sqrt(m-7)=n+3 is m=n^2+6n+16 {n>=-3}

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solvefor m,sqrt(m-7)=n+3

solve for

m, m - 7 = n + 3

m = n^{2} + 6 n + 16 {n \geq - 3}

Solution steps

m - 7 = n + 3

Square both sides:

m - 7 = n^{2} + 6 n + 9

m - 7 = n^{2} + 6 n + 9

Solve

m - 7 = n^{2} + 6 n + 9 : m = n^{2} + 6 n + 16

m = n^{2} + 6 n + 16

Verify Solutions:

m = n^{2} + 6 n + 16 {n \geq - 3}

The solution is

m = n^{2} + 6 n + 16 {n \geq - 3}

6 x + 67 + 15 = 20

3 x + 70 = x

x^{- \frac{2}{3}} = \frac{1}{9}

x, x^{2} - 9 = 0

3 x^{\frac{4}{3}} = 0

What is the answer to solvefor m,sqrt(m-7)=n+3 ?
The answer to solvefor m,sqrt(m-7)=n+3 is m=n^2+6n+16 {n>=-3}