What are the solutions to the equation (2x+7)^2=81 ?

The solutions to the equation (2x+7)^2=81 are x=1,x=-8

Find the zeros of (2x+7)^2=81

The zeros of (2x+7)^2=81 are x=1,x=-8

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(2 x + 7)^{2} = 81

x = 1, x = - 8

Solution steps

(2 x + 7)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 7 = 81 : x = 1

Solve

2 x + 7 = - 81 : x = - 8

The solutions to the quadratic equation are:

x = 1, x = - 8

π (1 + \frac{e - e ^{- 1}}{4})

\frac{2 ( n + 1 ) ( 2 ( n + 1 ) + 1 ) ( 4 ( n + 1 ) + 1 )}{6}

- 12 \leq - 3 g

12 x^{2} - 13 x y - 4 y^{2}

\frac{1}{4} + \frac{1}{12}

What are the solutions to the equation (2x+7)^2=81 ?
The solutions to the equation (2x+7)^2=81 are x=1,x=-8
Find the zeros of (2x+7)^2=81
The zeros of (2x+7)^2=81 are x=1,x=-8