What is the answer to 13=sqrt((6-1)^2+(y-3)^2) ?

The answer to 13=sqrt((6-1)^2+(y-3)^2) is y=15,y=-9

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13=sqrt((6-1)^2+(y-3)^2)

13 = (6 - 1)^{2} + (y - 3)^{2}

y = 15, y = - 9

Solution steps

13 = (6 - 1)^{2} + (y - 3)^{2}

Square both sides:

169 = y^{2} - 6 y + 34

169 = y^{2} - 6 y + 34

Solve

169 = y^{2} - 6 y + 34 : y = 15, y = - 9

y = 15, y = - 9

Verify Solutions:

y = 15

True

, y = - 9

True

The solutions are

y = 15, y = - 9

(\frac{x}{1 - x})^{- 0.5} = 1.732

2 x - 1 = x + 1

4 + y = 1

5 - x - 1 = x

What is the answer to 13=sqrt((6-1)^2+(y-3)^2) ?
The answer to 13=sqrt((6-1)^2+(y-3)^2) is y=15,y=-9
Solve for y: 13=sqrt((6-1)^2+(y-3)^2)
The solution is y=15,y=-9