What is the answer to 2x-1=sqrt(x+3) ?

The answer to 2x-1=sqrt(x+3) is x=(5+sqrt(57))/8

Solve for x: 2x-1=sqrt(x+3)

The solution is x=(5+sqrt(57))/8

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2 x - 1 = x + 3

x = \frac{5 + 57}{8}

Decimal Notation

x = 1.56872 \dots

Solution steps

2 x - 1 = x + 3

Square both sides:

4 x^{2} - 4 x + 1 = x + 3

4 x^{2} - 4 x + 1 = x + 3

Solve

4 x^{2} - 4 x + 1 = x + 3 : x = \frac{5 + 57}{8}, x = \frac{5 - 57}{8}

x = \frac{5 + 57}{8}, x = \frac{5 - 57}{8}

Verify Solutions:

x = \frac{5 + 57}{8}

True

, x = \frac{5 - 57}{8}

False

The solution is

x = \frac{5 + 57}{8}

6 y + 4 = 4 y + 1 + 1

a, b = a + b + 4

4 x^{\frac{1}{2}} = x

0 = x^{2} - 4

x, xu = 1 + 2 x

What is the answer to 2x-1=sqrt(x+3) ?
The answer to 2x-1=sqrt(x+3) is x=(5+sqrt(57))/8
Solve for x: 2x-1=sqrt(x+3)
The solution is x=(5+sqrt(57))/8