What is the answer to cube root of 2-x}=1-\sqrt{x-1 ?

The answer to cube root of 2-x}=1-\sqrt{x-1 is x=2,x=1,x=10

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cube root of 2-x}=1-\sqrt{x-1

x = 2, x = 1, x = 10

Solution steps

Rewrite the equation with

and

x = - u^{3} + 2

u = 1 - (- u^{3} + 2) - 1

Solve

u = 1 - (- u^{3} + 2) - 1 : u = 0, u = 1, u = - 2

u = 0, u = 1, u = - 2

Substitute back

solve for

x

Solve

x = 2, x = 1, x = 10

Verify Solutions:

x = 2

True

, x = 1

True

, x = 10

True

The solutions are

x = 2, x = 1, x = 10

7 - X = 5 X - 29

7 - x - 19 + x = - 2

2 x + 5 - 3 = 0

x^{\frac{1}{2}} = \frac{1}{3}

- 2 = x^{\frac{- 1}{2}}

What is the answer to cube root of 2-x}=1-\sqrt{x-1 ?
The answer to cube root of 2-x}=1-\sqrt{x-1 is x=2,x=1,x=10
Solve for x: cube root of 2-x}=1-\sqrt{x-1
The solution is x=2,x=1,x=10