What is the answer to sqrt(x^2-4x+4)=2x-1 ?

The answer to sqrt(x^2-4x+4)=2x-1 is x=1

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sqrt(x^2-4x+4)=2x-1

x^{2} - 4 x + 4 = 2 x - 1

x = 1

Solution steps

x^{2} - 4 x + 4 = 2 x - 1

Square both sides:

x^{2} - 4 x + 4 = 4 x^{2} - 4 x + 1

x^{2} - 4 x + 4 = 4 x^{2} - 4 x + 1

Solve

x^{2} - 4 x + 4 = 4 x^{2} - 4 x + 1 : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions:

x = 1

True

, x = - 1

False

The solution is

x = 1

- \frac{1}{1 - x ^{2}} = 0

3 x - 14 = 5

x - 4 x = 0.1

0 = 1 - x^{2}

What is the answer to sqrt(x^2-4x+4)=2x-1 ?
The answer to sqrt(x^2-4x+4)=2x-1 is x=1
Solve for x: sqrt(x^2-4x+4)=2x-1
The solution is x=1