What is the answer to 2=(k+sqrt(k^2-8))/2 ?

The answer to 2=(k+sqrt(k^2-8))/2 is k=3

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2=(k+sqrt(k^2-8))/2

2 = \frac{k + k ^{2} - 8}{2}

k = 3

Solution steps

2 = \frac{k + k ^{2} - 8}{2}

Multiply both sides by

2

2 \cdot 2 = \frac{k + k ^{2} - 8}{2} \cdot 2

Simplify

4 = k + k^{2} - 8

Remove square roots

16 - 8 k + k^{2} = k^{2} - 8

Solve

16 - 8 k + k^{2} = k^{2} - 8 : k = 3

k = 3

Verify Solutions:

k = 3

True

The solution is

k = 3

x, x - 9 - 3 x = 0

22 - t = 2 + 3 t

3 x - 3 + 2 x + 8 + 1 = 0

1 = 2 x

2 - x - 2 x + 1 = 0

What is the answer to 2=(k+sqrt(k^2-8))/2 ?
The answer to 2=(k+sqrt(k^2-8))/2 is k=3
Solve for k: 2=(k+sqrt(k^2-8))/2
The solution is k=3